題目 Problem The absolute maximum value of f(x)=sinx2−cosxf(x) = \frac{\sin x}{2-\cos x}f(x)=2−cosxsinx over the closed interval [0,π][0, \pi][0,π] is (3)‾\underline{\quad(3)\quad}(3). The absolute minimum value of f(x)f(x)f(x) over [0,π][0, \pi][0,π] is (4)‾\underline{\quad(4)\quad}(4).