題目 8. (10 points) Given function T(x,y)=1+x2−y2T(x,y)=1+x^2-y^2T(x,y)=1+x2−y2, find the curve γ(t)=(x(t),y(t))\gamma(t)=\bigl(x(t),y(t)\bigr)γ(t)=(x(t),y(t)) so that γ(0)=(1,4)\gamma(0)=(1,4)γ(0)=(1,4) and γ′(t)=−∇T(γ(t))\gamma'(t)=-\nabla T(\gamma(t))γ′(t)=−∇T(γ(t)). 解答
