題目 3. (10 points) Given f(t)={1,t≤01−t,t>0f(t)= \begin{cases} 1, & t\le 0 \\ 1-t, & t>0 \end{cases}f(t)={1,1−t,t≤0t>0 and F(x)=∫−12ax+2f(t) dtF(x)=\int_{-1}^{2ax+2} f(t)\,dtF(x)=∫−12ax+2f(t)dt with a>0a>0a>0, find aaa so that FFF is maximum at x=−2ax=-2ax=−2a. 解答