題目
9. (10%) Evaluate the double integral
∬Ry4−x4xydA,
where R is the region in the first quadrant bounded by x2+y2=4, x2+y2=9, y2−x2=1, y2−x2=4.
解答
解法一
令 u=x2+y2、v=y2−x2。第一象限中
∂(x,y)∂(u,v)=4xy,y4−x4=uv.
故
∬Ry4−x4xydA=41∫49∫14uv1dvdu=41ln49ln4.