題目 Problem (10 points) Find the following limits. limx→0sin(4x3)x.\lim_{x\to 0}\dfrac{\sin(4x^3)}{x}.x→0limxsin(4x3). 解答 解法一 sin(4x3)x=sin(4x3)4x3⋅4x2⟶0.\frac{\sin(4x^3)}x=\frac{\sin(4x^3)}{4x^3}\cdot4x^2\longrightarrow\boxed0.xsin(4x3)=4x3sin(4x3)⋅4x2⟶0.