題目 2. (10 points) If the function f(x)={sin(4x)+a−2b3x,x≠02a+b,x=0f(x)= \begin{cases} \dfrac{\sin(4x)+a-2b}{3x}, & x\ne 0 \\ 2a+b, & x=0 \end{cases}f(x)=⎩⎨⎧3xsin(4x)+a−2b,2a+b,x=0x=0 is continuous at x=0x=0x=0, then (a,b)=?(a,b)=?(a,b)=? 解答