題目
Problem
Let
f(x)=x−∫0x2e−t2dt
for x∈(−∞,∞). Which of the following statements is true?
(a) f is strictly decreasing on the interval (0,∞).
(b) f has a local minimum at 0.
(c) limx→0−f(x)=∞.
(d) f(x)<0 for x<0.
(e) None of the above statements is true.
解答
解法一
思路
展開
- 對 x<0,積分項為正而 x 為負,可立即判定函數值的符號。
答題過程
展開
當 x<0,有
∫0x2e−t2dt>0.
因此
f(x)=x−∫0x2e−t2dt<0.
所以答案為 (d)。