題目 Problem (F) Find the solution of the differential equation y′=(1+2x)(1+y2)y'=(1+2x)(1+y^2)y′=(1+2x)(1+y2) with the initial condition y(0)=1y(0)=1y(0)=1. Answer: (7)‾\underline{\quad(7)\quad}(7). 解答
